5v^2=16v-3

Solution for 5v^2=16v-3 equation:

5v^2=16v-3

We move all terms to the left:

5v^2-(16v-3)=0

We get rid of parentheses

5v^2-16v+3=0

a = 5; b = -16; c = +3;
Δ = b2-4ac
Δ = -162-4·5·3
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-14}{2*5}=\frac{2}{10}
=1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+14}{2*5}=\frac{30}{10}
=3
$